[Zope] Underscore Caracter

[T.J. Mannos]

Yep, it's there, but it's not documented.

Basically, anything in the python "string" module should be accessible from
Zope DTML.

Now, who do I have to beat up to get the 're' module added to the namespace
variable???  :)

- T.J.

-----Original Message-----
From: zope-admin@zope.org [mailto:zope-admin@zope.org]On Behalf Of Chris
McDonough
Sent: Tuesday, September 05, 2000 7:54 PM
To: T.J. Mannos
Cc: Marcus Mendes; zope@zope.org
Subject: RE: [Zope] Underscore Caracter


On Tue, 5 Sep 2000, T.J. Mannos wrote:
> Hmm.. Shouldn't that be:
>
> _.string.join(_.string.split('asd asd'), ' '), '_')

The second argument is implicit on string.split (it defaults to a single
space).  But your way works too.

> Or, alternatively (and more intuitively),
>
> _.string.replace('asd asd', ' ', '_')
> _.string.replace('asd_asd', '_', ' ')

It should be noted that _.string.replace() is not mentioned in the DTML
reference guide.  If it exists, it should be used.  Sigh.  I can't wait
for the Zope Book to come out, I'm going to be the first buyer.  ;-)

> Hi Marcus,
>
> This is untested.
>
> Turn "asd asd" into "asd_asd" and output:
>
> <dtml-var "_.string.join(_.string.split('asd asd'), '_')">
>
> Turn "asd_asd" into "asd asd" and output:
>
> <dtml-var "_.string.join(_.string.split('asd_asd', '_'))">
>
> On Sun, 3 Sep 2000, Marcus Mendes wrote:
> > Hello,
> >
> > I need replace 0x20 (space caracter ) to Undescore Caracter. I need also
> > a function that UNDO this operation. How can I to do this in DTML
> > sintaxe?
>

Chris McDonough
Digital Creations, Publishers of Zope
http://www.zope.org


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