[Zope] Sorting objectValues in Python Script

[Casey Duncan]

Ick, no lambda needed:

items = context.objectItems()
items.sort()
for id, object in items:
    print id, object
return printed

sort is *much* faster when you don't use a comparison function as well (though sometimes you do need them).

-Casey

On Fri, 18 Oct 2002 10:20:27 +0200
Jerome Alet <alet@librelogiciel.com> wrote:

> On Fri, Oct 18, 2002 at 10:15:10AM +0200, Andreas Tille wrote:
> > Hello,
> > 
> > I just want to build a sorted list of
> > 
> >    list = context.objectValues('ExtFile')
> >    for file in list:
> >         print file.id, file.title
> >    return printed
> 
> <UNTESTED>
> list.sort(lambda x,y : cmp(y.getId(), x.getId()))
> </UNTESTED>
> 
> hth
> 
> Jerome Alet