[Zope] Re: authentication with python program

Josef Meile jmeile at hotmail.com
Fri Apr 18 03:21:58 EDT 2008


Hi Miguel

First, you could drop the Unauthorized Exception from the error_log
object in the root folder of the zope management interface. Then
activate the verbose-security option in your zope.conf file. To do
this, you need to put/replace this lines:

security-policy-implementation python
verbose-security on

After you have done this, you need to restart zope, try again your
authentication script, and take a look at your event.log file or
the error_log object. You may find the reason of why is this failing.
In case you don't find it, then place the full traceback here.

Best regards
Josef

Miguel Beltran R. schrieb:
> I have this program what open a dtml what return a XML page, but I
> have error with permisions:
> 
> import urllib, urllib2
> 
> pagina = "http://10.28.1.239/bitacoras/alta/estado2.html"
> datos = {"btipo":"D",
>          "bholo":87654321,
>          "bplac":"dd-12345",
>          "accion":"alta_gasolina",
> }
> 
> params=urllib.urlencode(datos)
> aut=urllib2.HTTPBasicAuthHandler()
> aut.add_password("AFICON", pagina, "myuser", "mypass")
> opener=urllib2.build_opener(aut)
> urllib2.install_opener(opener)
> r=urllib2.urlopen(pagina,params)
> print r.read()
> r.close()
> 
> but returned XML say:
> <ajax>
>   <accion>alta_gasolina</accion>
>                <respuesta>error</respuesta>
>         <error_type>Unauthorized</error_type>
>         <error_description>You are not allowed to access 'zsql_alta'
> in this context</error_description>
> 
>   </ajax>
> 
> help? how I can send HTTPBasicAuth?
> 
> pd. Sorry by my bad english



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