[Zope] Re: NamedTemplate.__call__ not returning anything
Maurits van Rees
m.van.rees at zestsoftware.nl
Mon Jan 14 16:20:12 EST 2008
Dieter Maurer, on 2008-01-14:
> Maurits van Rees wrote at 2008-1-13 23:32 +0000:
>>I have some code where I try to get a named template and render it and
>>if it fails I render a default template instead. But this fails,
>>presumably because the __call__ method of NamedTemplate does not
>>return anything. From zope/formlib/namedtemplate.py (Zope 2.10):
>> def __init__(self, name):
>> self.__name__ = name
>> def __get__(self, instance, type=None):
>> if instance is None:
>> return self
>> return component.getAdapter(instance, INamedTemplate, self.__name__)
>> def __call__(self, instance, *args, **kw):
>> self.__get__(instance)(*args, **kw)
>>I seems strange to me that __call__ does not actually return
>>anything. Is it just me?
> It returns only if you use "return" (otherwise, it returns "None").
> Thus, try "return self.__get__(....)".
I know. :) I think you misunderstood me there. This class is from
core Zope (zope.formlib.namedtemplate). So to refrase my question:
why does this call method not do "return self.__get(....)"? Looks
like a bug to me, but this line has been there since 2005 and named
templates do seem to work fine, so I am confused.
Maurits van Rees | http://maurits.vanrees.org/
Work | http://zestsoftware.nl/
"This is your day, don't let them take it away." [Barlow Girl]
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